A 14 ohm resistor is to be installed in a series circuit carrying .05 ampere. How much power will the resistor be required to dissipate?

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Multiple Choice

A 14 ohm resistor is to be installed in a series circuit carrying .05 ampere. How much power will the resistor be required to dissipate?

Explanation:
Power dissipated by a resistor is given by P = I^2 R. With a current of 0.05 A through a 14 Ω resistor, P = (0.05)^2 × 14 = 0.0025 × 14 = 0.035 W, which is 35 milliwatts. You can also confirm by finding the voltage across the resistor: V = IR = 0.05 × 14 = 0.7 V, and P = VI = 0.7 × 0.05 = 0.035 W. This matches the calculation, so the resistor must dissipate 35 mW.

Power dissipated by a resistor is given by P = I^2 R. With a current of 0.05 A through a 14 Ω resistor, P = (0.05)^2 × 14 = 0.0025 × 14 = 0.035 W, which is 35 milliwatts. You can also confirm by finding the voltage across the resistor: V = IR = 0.05 × 14 = 0.7 V, and P = VI = 0.7 × 0.05 = 0.035 W. This matches the calculation, so the resistor must dissipate 35 mW.

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