A 6 cylinder engine with a bore of 3.5 inches, a height of 7 inches, and a stroke of 4.5 inches will have a total piston displacement of

A 6 cylinder engine with a bore of 3.5 inches, a height of 7 inches, and a stroke of 4.5 inches will have a total piston displacement of

• A. 180
• B. 300
• C. 275
• D. 259.77

Answer: (D)

Engine displacement comes from the volume the pistons sweep: for one cylinder it's the bore area times the stroke, and for the whole engine you multiply by the number of cylinders. Start with the bore as 3.5 inches, so the radius is 1.75 inches. The cross‑sectional area is πr^2 = π × (1.75)^2 ≈ 9.621 square inches. Multiply by the stroke of 4.5 inches to get the per‑cylinder displacement: 9.621 × 4.5 ≈ 43.295 cubic inches. With six cylinders, the total displacement is 6 × 43.295 ≈ 259.77 cubic inches. The height value given isn’t involved in this calculation. So the total piston displacement is about 259.77 in^3.

Engine displacement comes from the volume the pistons sweep: for one cylinder it's the bore area times the stroke, and for the whole engine you multiply by the number of cylinders. Start with the bore as 3.5 inches, so the radius is 1.75 inches. The cross‑sectional area is πr^2 = π × (1.75)^2 ≈ 9.621 square inches. Multiply by the stroke of 4.5 inches to get the per‑cylinder displacement: 9.621 × 4.5 ≈ 43.295 cubic inches. With six cylinders, the total displacement is 6 × 43.295 ≈ 259.77 cubic inches. The height value given isn’t involved in this calculation. So the total piston displacement is about 259.77 in^3.